Mathematics MCQs (Q41 – Q50)
Q41. What is the value of (56 ÷ 7) × 4 − 18 + 3²?
- A) 23
- B) 31
- C) 27
- D) None of these
Answer: A
56 ÷ 7 = 8, 8 × 4 = 32, 3² = 9. Therefore 32 − 18 + 9 = 23.
Q42. Simplify: 0.25 × 0.8 ÷ 0.05
- A) 2
- B) 3
- C) 4
- D) None of these
Answer: C
0.25 × 0.8 = 0.20 and 0.20 ÷ 0.05 = 4.
Q43. What percentage is 75 of 300?
- A) 20%
- B) 25%
- C) 30%
- D) None of these
Answer: B
(75 ÷ 300) × 100 = 25%.
Q44. How many numbers between 1 and 100 are divisible by both 3 and 5?
- A) 5
- B) 6
- C) 7
- D) None of these
Answer: B
LCM of 3 and 5 is 15. Multiples are 15, 30, 45, 60, 75, 90 = 6 numbers.
Q45. Which of the following is a perfect square?
- A) 2025
- B) 2030
- C) 2048
- D) None of these
Answer: A
45 × 45 = 2025, therefore it is a perfect square.
Q46. Two numbers are in ratio 5 : 8. If their sum is 104, the larger number is
- A) 40
- B) 56
- C) 64
- D) None of these
Answer: C
Total parts = 13. Larger number = (8/13) × 104 = 64.
Q47. If the cost of 15 pens is Rs 225, what is the cost of 28 pens?
- A) Rs 400
- B) Rs 420
- C) Rs 440
- D) None of these
Answer: B
Cost of one pen = 225 ÷ 15 = 15. Cost of 28 pens = 28 × 15 = 420.
Q48. Sum of ages of mother and daughter is 48. Four years ago mother was four times daughter’s age. Daughter’s present age is
- A) 10
- B) 12
- C) 14
- D) None of these
Answer: B
Let daughter = d. Solving equation gives d = 12.
Q49. A man’s age is three times his son’s age. After 10 years he will be twice his son’s age. Son’s present age is
- A) 8
- B) 10
- C) 12
- D) None of these
Answer: B
Let son’s age = x. Then 3x + 10 = 2(x + 10). Solving gives x = 10.
Q50. Price increased by 20% and then decreased by 20%. Net change is
- A) No change
- B) 4% increase
- C) 4% decrease
- D) None of these
Answer: C
100 → 120 → 96. Final value decreases by 4%.
